Search Results
Matches 1 to 2 of 2 for Last Name equals BRITTON AND Tree equals Marquardt
Last Name, Given Name(s) ![]() |
Born/Christened ![]() |
Person ID | Tree | ||
1 | ![]() | b. 26 Mar 1730 | Flemington, Hunterdon, New Jersey, USA ![]() | P1148 | Marquardt |
2 | ![]() | b. 1690 | P1265 | Marquardt |